Question

the volume occupied by 1 moleule of h2o​

Answer 1

Answer:

volume occupied by one molecule = GmW / d × Na

d = 1 g / ml of h2o ..

= 18 / 1 × 6.022 × 10 ^ 23

= 3 × 10 ^-23

Answer 2

$\huge\underline\green{\sf Answer}$

$\large{\boxed{\sf 3×{10}^{-24}}}$

$\huge\underline\green{\sf Solution}$

★ Density of water = 1000 g/L

★The gram molecular mass of water is =18.02

No. of mole in 1L =$\sf{{\frac{1000}{18.02}}}$

★No. Of Mole = 55.5 Mole

Number of Molecule in 55.5 Mole of Water :-

$\sf{55.5×6.023×{10}^{23}}$

$\sf{3.34×{10}^{25}}$

According to Question 1 molecule of water :-

$\sf{={\frac{1}{3.34×{10}^{25}}}}$

$\large{\boxed{\sf 3 ×{10}^{-24}}}$

✨⛄⛄⛄✨