The volume occupied by 23g of NO2 at NTP is ______ cm3.
Answers
Answered by
2
Answer:
Mass of one mole of nitrogen dioxide = 14 + 16 + 16 = 46g
No. of moles in 0.23g on NO2 = 0.005
volume occupied by 1 mole = 22.4 L
volume occupied by 0.005 mole = 0.112 L OR 112 mL:
Explanation:
Similar questions