Question

The volume occupied by 3.5 g of O2 at 740mm pressure and 27 degree Celsius. Using Mole concept and Avogadro's law.

Answer 1

here's yer answer all d best for chem

Answer 2

Answer: The volume occupied by oxygen gas is 2.757L

Explanation:

Number of moles is calculated by using the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

We are given:

Mass of oxygen gas = 3.5g

Molar mass of oxygen gas = 32 g/mol

Putting values in above equation, we get:

$\text{Moles of oxygen gas}=\frac{3.5g}{32g/mol}=0.109mol$

To calculate the volume occupied by given amount of gas, we use the ideal gas equation, which is:

$PV=nRT$

where.

P = pressure of the gas = $\frac{740mmHg}{760mmHg}\times 1atm=0.9736atm$    (Conversion Factor: 1 atm = 760mmHg)

V = volume occupied by this gas = ?L

T = temperature of the gas = [27 + 273]K = 300K

n = Number of moles of oxygen gas = 0.109mol

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

Putting values in above equation, we get:

$0.9736atm\times V=0.109mol\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 300K\\\\V=2.757L$

Hence, the volume occupied by oxygen gas is 2.757L