the volume occupied by 4.4 gram of co2 at STP is
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Answer:
2.24 L
Explanation:
molar mass ( CO2) = 44 g
mole = givenmass / molar mass
n = 4.4/44 = 0.1
since one mole occupies 22.4L at stp
0.1 mole occupies 0.1 × 22.4 = 2.24L
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