the volume of 0.05 K2Cr2O7 solution which can oxidise 200ml of 0.1M FeSO4 solution in acidic medium is
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Answer:
400ml
Explanation:
Data
V1 of k2CrO7 =?
M1 of K2CRO7 = 0.05
V2 of FeSO4 = 200
M2 of FeSO4 = 0.1
formula M1V1 = M2V2
0.05 multiply V1 = 0.1 multiply 200
0.05 multiply V1 = 20
V1 = 20/0.05
V1 of K2CRO7 = 400ml
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