Question

the volume of 0.05N na2co3 solution required to neutralize 200ml of 0.02 M h2so4​

Answer 1

Answer:

See below.

Explanation:

We are given 0.05 N Na2CO3 and 200 ml of 0.02 M H2SO4. For neutralization, we should have equal gram equivalents of Na2CO3 and H2SO4.

Gram equivalent = normality * volume

Or,

Gram equivalent = ( n-factor * molarity ) * volume

So, for Na2CO3,

$N_{1}V_{1}=0.05\left( V_{1}\right)$

For H2SO4,

$\left( 200\right) \left( 0.02\right) \left( 2\right) =8$

Equating both of them,

$\begin{aligned}8=0.05V_{1}\\ V_{1}=160ml\end{aligned}$

which gives us the answer. Hence 160 ml of Na2Co3 is required.

Tip: For such problems, always equate/add the gram equivalents. Use the two formulae to calculate gram equivalents.

Answer 2

Explanation:

please see the attachment

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