Question

The volume of 1 L water upon vapourisation at STP is nearly
(1) 124.3 L (2)1244.4 L
(3)1 L (4)22.4 L

Answer 1

The molarity of 1 lire water is 55.5 ie no. of moles of water in 1 litre of it is 55.5 , there fore volume occupied by vapours of it is = 55.5 x 22.4 l = 1243L

since volume of 1 mole of a gas or vapour is 22.4 litre.

I hope help you

Answer 2

Answer:

We already know the value of the density of water which is 1 g/mL.

So, we can find the amount of the moles of water present in 1000ml.

Hence, 1000 mL or 1 L of water will have = 1000/18 moles = 55.56 moles.

This 55.56 is the molarity of the water.

As in the given question it is asked about STP hence we get that:

The volume of 1 mole of water on vaporization or of any gas is 22.4L.

So, know we know that the volume of 55.56 moles of water is :

55.56*22.4 L= 1244.44L .