Question

the volume of 11gm CO2 at NTP is ...................... ?​

Answer 1

Answer:

5.6 L

Molecular weight of CO2 = 44. So 44 g of CO2 will occupy= 22.4 L at NTP. So 11 g of CO2 will occupy =22.4x11/44 = 5.6 L at NTP .

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Answer 2

Answer:

5.6 L

Molecular weight of CO2 = 44. So 44 g of CO2 will occupy= 22.4 L at NTP. So 11 g of CO2 will occupy =22.4x11/44 = 5.6 L at NTP .

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