the volume of 1M hcl needed to dissolve 10g of calcium carbonate
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Given:- 1M hcl dissolve 10g of calcium carbonate
To find:- The volume of 1M hcl needed to dissolve 10g of calcium carbonate
Solution:- According to the question,
Let a moles of CaCO3 present in 10gm of mixture
So a × 100 = 10 or, a= 0.01 mole
so,
M.l eq of HCl = M.l eq of CaCO3
or, 1×V×1 = 2×0.01×1000
or, V = 20 ml
So, 20 ml of 1M hcl needed to dissolve 10g of calcium carbonate
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