Question

The volume of 2.8g of carbon monoxide at 27°c and 0.0821 atm is

Answer 1

2.24 l will be the ans

Answer 2

Answer: The volume of carbon monoxide gas is 30 L

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\tet{Given mass}}{\text{Molar mass}}$

Given mass of carbon monoxide = 2.8 g

Molar mass of carbon monoxide = 28 g/mol

Putting values in above equation, we get:

$\text{Moles of CO}=\frac{2.8g}{28g/mol}=0.1mol$

To calculate the volume of gas, we use the equation given by ideal gas, which is:

PV = nRT

where,

P = Pressure of the gas = 0.0821 atm

V = volume of the gas = ? L  

n = no of moles of gas =  0.1 mol

R = Gas constant = $0.0821\text{L atm }mol^{-1}K^{-1}$

T = Temperature of the gas = 27°C = 300 K   (Conversion factor: $T(K)=T(^oC)+273$ )

Putting values in above equation, we get:

$0.0821atm\times V=0.1mol\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 300K\\\\V=30L$

Hence, the volume of carbon monoxide gas is 30 L