Question

the volume of 4.4 g at NTP will be

Answer 1

At NTP, normal temperature and pressure .
Temperature, T = 25°C = 298K
pressure, P = 1atm

given, weight of CO2 = 4.4g

molecular weight of CO2 = 12 + 2 × 16 = 44g/mol

number of mole of CO2, n = 4.4/44 = 0.1

we know, PV = nRT

V = nRT/P = 0.1 × 0.082 × 298/1 = 2.4436L

hence, volume of carbon dioxide at NTP = 2.44L

but when we want to find volume of gas at STP,
use Temperature, T = 0°C = 273K

so, V = nRT/P = 0.1 × 0.082 × 273/1 = 2.2386L

hence, volume of carbon dioxide = 2.24L at STP