The volume of 4g of H2 at 4 atmospheres?
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Hi friend,
Assuming the temperature to be 273k
PV = nRT
thus V = nRT/P
n = no. of moles = 4/2 = 2 ( moler mass H2 = 2 )
So, V= 2 × 0.082×273/4
= 11.193 liters
....i hope it helps you
================================
# Be brainly !!
mark me as a brainlist.
Assuming the temperature to be 273k
PV = nRT
thus V = nRT/P
n = no. of moles = 4/2 = 2 ( moler mass H2 = 2 )
So, V= 2 × 0.082×273/4
= 11.193 liters
....i hope it helps you
================================
# Be brainly !!
mark me as a brainlist.
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