the volume of a block is 5 cm3 . if the density of the block is 250 g/cm3 , what is the mass of the block ( please give your answer in step by step )
Answers
Answer:
ANSWER
Density of block =5 gm/cm
2
Volume of block V=(5×5×5)cm
3
=125cm
3
Mass of block.M=density × volume
=5×125
=325 gm=0625 kg
Density of water, ρ=1 gm/cm
3
On submerging the iron block completely into water the apparent weight of the block is given from the box of the container
Drawing free body diagram of the block
Now as the block is stationery upwards and downward form on the block should balance each other
Thus. N+F
B
=Mg
Now, F
B
= density of water × volume of block × g
=(1 gm/cm
3
)×(125cm
3
)×(98 m/s
2
)
=(125 gm)×(98 m/s
2
)
=(0.125×9.8) kgm/s
2
=(0.125×9.8)N(1 N=1 kgm/s
2
)
Putting values is (1)
N=(0.625×9.8)−(0.125×9.8) Newton
⇒ Apparent weight =(0.5×9.8) Newton
(∵ Apparent weight = normal force)
Now, 1 gf(gram−force)=9.8×10
−3
N
⇒1 N=
9.8
1
×10
3
gf
Thus, Apparent weight +(0.5×9.8)×(
9.8
1
×10
3
)
=500 gf
Hence apparent weight of the block completely submerged in water is 500 gram- force
Explanation:
Answer:
density = mass/ volume
250 = mass/ 5
mass = 250 × 5
= 1050g