the volume of a cone is 9856 CM if the diameter of its base is 28 cm what is its height and its slant height
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HEIGHT=48 CM
SLANT HEIGHT=50CM
SLANT HEIGHT=50CM
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Given diameter of the base of the cone is 28cm, therefore radius is = 28/2 = 14cm
Volume of the cone = 9856cm³
Therefore 1/3πr²h = 9856cm³
=> 1/3×22/7×14×14×h = 9856cm²
=> 22/3×2×14×h = 9856cm³
=> 616/3×h = 9856cm³
=> h = 9856/1×3/616
=> h = 16×3
=> h = 48cm
Verification:-
Volume of the cone = 1/3πr²h
= 1/3×22/7×14×14×48
= 22/3×2×14×48
= 29568/3
= 9856cm³
Hence, the height of the cone is 48cm.
Now, by Pythagoras thereom we will find the slant height.
Let slant height be hypontuse.
a² + b² = c²
14² + 48² = c²
196 + 2304 = c²
2500 = c²
c = √2500
c = 50cm
Slant height of the cone is 50cm.
Hope my answer is right...
Volume of the cone = 9856cm³
Therefore 1/3πr²h = 9856cm³
=> 1/3×22/7×14×14×h = 9856cm²
=> 22/3×2×14×h = 9856cm³
=> 616/3×h = 9856cm³
=> h = 9856/1×3/616
=> h = 16×3
=> h = 48cm
Verification:-
Volume of the cone = 1/3πr²h
= 1/3×22/7×14×14×48
= 22/3×2×14×48
= 29568/3
= 9856cm³
Hence, the height of the cone is 48cm.
Now, by Pythagoras thereom we will find the slant height.
Let slant height be hypontuse.
a² + b² = c²
14² + 48² = c²
196 + 2304 = c²
2500 = c²
c = √2500
c = 50cm
Slant height of the cone is 50cm.
Hope my answer is right...
anuritha:
very good effort
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