the volume of a cubical solid is 10368 cm cube if its dimensions are in the ratio 3 : 2 : 1 find the find the cost of polishing its total surface @ rupees 2.5 per metre square
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let the common factor be x
length=3x
breadth=2x
height=x
volume=l×b×h
length=3x=12×3=36cm =0.36m
breadth=2x=2×12=24cm=0.24m
height=x=12cm=0.12m
total surface area=2(lb+bh+lh)
=2(0.36×0.24+0.24×0.12+
0.36×0.12)
=2(0.1584)
=0.3168m^2
cost for 2.5 m^2
=0.3168×2.5
=0.792m^2
length=3x
breadth=2x
height=x
volume=l×b×h
length=3x=12×3=36cm =0.36m
breadth=2x=2×12=24cm=0.24m
height=x=12cm=0.12m
total surface area=2(lb+bh+lh)
=2(0.36×0.24+0.24×0.12+
0.36×0.12)
=2(0.1584)
=0.3168m^2
cost for 2.5 m^2
=0.3168×2.5
=0.792m^2
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