The volume of a cuboid is X³-7X+6 , then the longest side of the cuboid is.?
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Answered by
27
x^3 - 7x + 6
= x^3 - 4x - 3x + 6
= x (x^2 - 4) - 3(x-2)
= x [(x) ^2 - (2)^2] - 3(x-2)
= x (x-2)(x+2) - 3(x-2)
= (x-2) [ x (x + 2) - 3]
= (x - 2) [ x^2 + 2x - 3]
= (x-2) [ x^2 + 3x - x- 3]
= ( x - 2)[ x (x+3) - 1(x-3)]
= (x-2)(x-1)(x+3)
Sides are (x-2), (x-1) and (x+3)
Longest side = x+3
= x^3 - 4x - 3x + 6
= x (x^2 - 4) - 3(x-2)
= x [(x) ^2 - (2)^2] - 3(x-2)
= x (x-2)(x+2) - 3(x-2)
= (x-2) [ x (x + 2) - 3]
= (x - 2) [ x^2 + 2x - 3]
= (x-2) [ x^2 + 3x - x- 3]
= ( x - 2)[ x (x+3) - 1(x-3)]
= (x-2)(x-1)(x+3)
Sides are (x-2), (x-1) and (x+3)
Longest side = x+3
sushant2505:
Check 6th line common between them is (x-2)
Answered by
1
Answer:
Longest side of cuboid is x+3.
Step-by-step explanation:
Given volume of cuboid = x³ - 7x + 6
= x³ - 4x - 3x + 6
= x (x² - 4) - 3(x-2)
= x [x² - 2²] - 3(x-2)
∵ a² - b² = (a + b)(a - b)
= x (x+2)(x-2) - 3(x-2)
Taking (x - 2) common
= (x-2) [ x (x + 2) - 3]
= (x - 2) [ x² + 2x - 3]
= (x-2) [ x² + 3x - x- 3]
= ( x - 2)[ x (x+3) - 1(x-3)]
= (x - 2)(x - 1)(x + 3)
∵ Volume of cuboid = length × width × height
So sides of cuboid are (x - 2), (x - 1) and (x + 3)
And longest side is x+3
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