Question

The volume of a drop of rain was found to be 0.448 ml at ntp how many molecules of water and numbers of atoms of hydrogen are present

Answer 1

Hey Mate here is your Ans

Taking the density of water to be = 1 g/cm³ or 1g/ml

Mass = Density x Volume

Mass of water = 1 x 0.448 = 0.448g

Molar mass of water, H2O = 2x1 + 16 = 18g/mol

Moles of water = 0.448/18 = 0.0249

Avogadro's number = 6.022 x 10^23

Number of molecules of water = 6.022 x 10^23 x 0.0249

                                                = 1.5 x 10^22

1 molecule of water has 2 hydrogen atoms

Number of hydrogen atoms = 2 x 1.5 x 10^22

                                             = 3 x 10^22

I hope you have understood.

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Answer 2

SOLUTION:

we know that,

no of mole in 22.4 litre = 1 mole

then no of moles in 1 litre = 1/ 22.4 moles

given volume = 0.448 ml = 448 litre

so, no of moles in 448 litre = 448/22.4 moles = 20 mole

no of molecules in 1 mole = 6.02 × 10 ^ 23

so no of molecules in 20 mole = 20 × 6.02 × 10^ 23 = 1.204 × 10^ 25

no of atom present in water = 3 × 1.204 × 10^ 25 = 3.612 × 10^ 25 atom

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