Question

The volume of a drop of rain was found to be 0.448ml at N.T.P. how many molecules of water and number of atom of hydrogen are present in this drop​

Answer 1

Answer:

taking the density of water=1g/cm³or 1g/ml

mass=density×volume

mass of water=1×0.448=0.448g

Mollar mass of water=h20×2×1=18g/mol

moles of water=0.448/18=0.0249

avogadro's number=6.022×10^23

Number of molecules of water=6.022×10^23×0.0249=1.5×10^22

1 molecules of water has 2 hydrogen atoms

no. of hydrogen atoms =2×1.5×10^22=3×10^22