Question

The volume of a gas decreases from 500 cc to 300 cc when a sample gas is compressed by an average pressure of 0.6 atm during this process 10 j of heat is liberated the change in internal energy is

Answer 1

U=q+w. since heat is realeased q=-10. w=-p(v2-v1). =-120×10^-6=-0.000120. so. U =-(10+0.00012)=-10.000120

Answer 2

Answer:

2.16J

Explanation:

Here: change in volume, 500cc - 300cc = 0.2L

Pressure P = 0.6atm

Q = -10J

Work done = P(dV)

= 0.12 L-atm

1 L-atm = 101.3J

this means, work done = 12.156J

therefore change in internal energy

dU = Q + W

= -10 + 12.156

= 2.156J