Question

The volume of a gas is reduced adiabatically to 1/4 of its
volume at 27ºC. If γ = 1.4 the new temperature is
(a) (300) 2⁰.⁴ K (b) (300) 2¹.⁴ K
(c) 300 (4)⁰.⁴ K (d) 300 (2)¹.⁴ K

Answer 1

Explanation:

For adiabatic change, the equation is

TV

γ−1

= constant

T

1

V

1

γ−1

−T

2

V

2

γ−1

(27+273)V

1

γ−1

=T

2

(

4

V

1

)

γ−1

300×V

1

γ−1

=

4

γ−1

T

2

×V

1

γ−1

⇒T

2

=300×4

γ−1

T

2

=300×4

1.4−1

=300×4

0.4

K

Hence, option A is correct