Question

The volume of a gas with a pressure of 1.2 atm increases from 1.0 l to 4.0 l. what is the final pressure of the gas, assuming constant temperature

Answer 1

pv= constant
p1v1=p2v2
since temp. is constant(pv=nRt)all term of rhs constant.
1.2*1=4*p2
or p2=1.2/4
= .3atm