Question

the volume of a metallic bob of mass 700g is 350 cube cm.
1)find the density of the bob.
2)when immersed in water what weight of water will be displaced by the bob?

Answer 1

Since , Volume of bob = 350 cm ^3
And Mass of bob = 700 g

1. Density = Mass / Volume i.e. 700 / 350 i.e. 2 g / cm ^ 3

2. Since , the Archimedes' Principle states that the volume of body immersed in the liquid will displace the same amount that was immersed therefore the immersed part of the body will displace the same amount of liquid as immersed.

HOPE YOU GOT IT...

Answer 2

Given,

Volume of the metallic bob = 350cm^3

Mass = 700g

We know,

1)Density=Mass/ Volume

So, Density = 700/ 350

Or, Density =2g/cm^3

The density of the bob is 2g/cm^3

2)

According to Archimedes law,

Weight of the displaced water is the same as weight of the bob.

So,

The weight of the displaced water = mg [ g = 9.8m/s^2 and m is the mass]

So, The weight of the displaced water = .7 × 9.8 [ as 700g = .7kg]

= 6.86 N

Hope it helps.