The volume of a mettalic cylinder pipe is 748 cm³. Its length is 14 cm and its external radius is 9cm . find its thickness. answer the question fast .its urgent
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The volume of a cylinder is given by Pi*r^2*h and the volume of a pipe is given by pi*(r1^2-r2^2)*h where r1 = external radius and r2 is the internal radius.
In this case, volume is 748, while r1 = 9cm and h =14cm. We need to find r2.
Substituting the values of volume, r1 and h in the above equation of volume of pipe, we get
748 = pi * (81-r2^2) * 14
Thus, 81-r2^2 = 748/(14*pi)
Or 81-r2^2 = 17.
r2^2 = 81-17 = 64.
Thus, r2 = sqrt(64) = 8.
Inner radius is 8cm and the thickness is 9cm - 8cm = 1cm.
Thus, the thickness of the pipe is 1cm.
In this case, volume is 748, while r1 = 9cm and h =14cm. We need to find r2.
Substituting the values of volume, r1 and h in the above equation of volume of pipe, we get
748 = pi * (81-r2^2) * 14
Thus, 81-r2^2 = 748/(14*pi)
Or 81-r2^2 = 17.
r2^2 = 81-17 = 64.
Thus, r2 = sqrt(64) = 8.
Inner radius is 8cm and the thickness is 9cm - 8cm = 1cm.
Thus, the thickness of the pipe is 1cm.
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