Physics, asked by Ankur127, 1 year ago


The volume of a parallelepiped constructed on the three vectors a = 3i+2j-k,
T = 2i+j+2k and c=i-3 j-k, is equal to
(A) 10 cu. Unit (B) 20 cu. Unit (C) 30 cu. Unit (D) 40 cu. Unit​

Answers

Answered by priyanka978576
0

Answer:

T=2i+j+2k and c=i_3 j_k,is equal to

answer :10 cu.unit

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