The volume of a parallelepiped constructed on the three vectors a = 3i+2j-k,
T = 2i+j+2k and c=i-3 j-k, is equal to
(A) 10 cu. Unit (B) 20 cu. Unit (C) 30 cu. Unit (D) 40 cu. Unit
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T=2i+j+2k and c=i_3 j_k,is equal to
answer :10 cu.unit
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