Question

The volume of a right circular cone is 100 pi cm 3 and its heightis 12cm find its slant height and hence its curved surface area.

Answer 1

Since volume of cone = 1/3Πr²h
nd given that  h=12cm
           volume = 100Πcm³
now,  1/3 x Π x r² x 12 = 100Π
         ∴  r = 5cm
now , slant height  l² = 5²+12²
                              l² =  169
                              l = 13cm
Hence, curved surface area = Πrl
                                             = Π x 5 x 13
                                             = 65Π cm²

Answer 2

Answer:

The circular cross section cone's inclination height is 13 cm.

step-by-step explanation:

The surface area of a cone is the space covered by the surface or perimeter of a cone. It is consistently expressed in square units. The shape of a cone is produced by stacking several triangles and spinning them around in an axis. Due to its flat base, it has a large surface area as well as a contact surface region. A cone can be categorized as either an angled cone or a right circular cone.

The volume of right circular cone $=100\pi cm^{3}$

height $= 12 cm$

The volume of the right circular $=(\frac{1}{3} )\pi ^{2} h$

$l^{2} =r^{2} +h^{2}$

The volume of the right circular cone $=(\frac{1}{3}\pi r^{2}h )$

$100\pi =(\frac{1}{3} )\pi r^{2} *12$

$r^{2} =25$

$l^{2} =l^{2} +h^{2}$

$l^{2} =25+12^{2}$

$l^{2} =25+144$

$l^{2} =169$

$l=13$

the height of the right circular cone is $13cm$

Hence, curved surface area $=\pi rl$

                                               $=\pi *5*13$

                                               $=65\pi cm^{2}$

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