The volume of a road roller whose diameter is 140 cm and the length is 2.2 m .it takes 400 revolutions to a level a stretch 2.2 m wide. find the surface are of stretch of road leveled in meter sq.
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Answer:
3872 m square
Step-by-step explanation:
given diameter of roadroller = 140cm = 1.4m
radius will be 0.7
length of roller = 2.2 m
therefore, CSA = 2×22/7×0.7×2.2
= 9.68 cm^2
It takes 400 revolutions to level a stretch 2.2m wide
therefore the surface area of road levelled =
400 × 9.68 m^2
= 3872.00 m^2
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