Question

the volume of a sphere is 38808 cm cube . find the cost of painting it at rate of rupees 10 per cm square

Answer 1

$\sqrt[3]{38808 \times 3 \div 4} = \sqrt[3]{9702 \times 3}$
=
$9 \times \sqrt[3]{28} \times \pi \times 9 \times \sqrt[3]{28} \times 10$

Answer 2

Given..Volume of sphere=38808 cubic cm
4/3×πr^3=38808
4/3×22/7×r^3=38808
r^3=38808×21 / 88
r^3=9261
r=21 cm
Now..to find the cost of painting we need the area to be painted i.e.,
4πr^2=4×22/7×21×21
=88×63
=5544 cm sq.
Now, Cost of painting 1 cm^2= 10 Rs.
Cost of painting 5544cm^2=5544×10
=55440 Rs...



Thank You !