Question

The volume of ch4 at ntp is formed when 20.5 g of ch3coona is treated with soda lime

Answer 1

     

Answer:

volume of CH₄ = 5.6 dm³.

Explanation:

equation: CH₃COONa + NaOH  →  Na₂CO₃ + CH₄

RMM of CH₃COONa = 12 + 3 + 12 +16 + 16 + 23

                                  = 82g.

               Mass of CH₃COONa         Volume of CH₄

                             82g                 →         22.4 dm³ (1RMM = 22.4 vol)

                           20.5g                →                x

x = 22.4×20.5/82          

x = 5.6 dm³