Question

the volume of gas in discharge tube is 1.12×10-7 ml at STP.then the number of molecule of gas in the tube is

Answer 1

Hey dear,

● Answer -
3.011×10^12 molecules

● Explaination -
# Given -
V = 1.12×10^-7 ml = 1.12×10^-10 L

# Solution -
1 mol of gas contains 22.41 L at STP.

Moles of gas are calculated by -
n = V / Vo
n = 1.12×10^-10 / 22.41
n = 5×10^-12 moles

No of gas molecules are calculated by -
N = n × No
N = 5×10^-12 × 6.022×10^23
N = 3.011×10^12 molecules

Given volume of gas contains 3.011×10^12 molecules.

Hope this helps you.
Keep asking..

Answer 2

Answer:

3.011*10¹²

Explanation:

it is correct answer