the volume of methane at NTP formed from 8.2 grams of sodium acetate by fusion with soda lime is ?
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Answered by
17
The volume of methane produced will be 3.75ml
The above reaction can be written as :
CH₃COONa + NaOH = CH₄ + Na₂CO₃
From the reaction it is clear that 1 mole of sodium acetate will produce 1 mole of methane
molecular weight of sodium acetate = 82 g
=> number of moles in 8.2 gms = 8.2/82 = 0.1 mole
Hence 0.1 mole of sodium acetate will produce 0.1 mole of methane.
since the molecular weight of methane is 16, therefore
0.1 mole of methane = 16 x 0.1 = 1.6 gms of methane
density of methane = 0.4256 g/ml
=> volume = mass / density
= 1.6/0.4256 = 3.75 ml
Hence the volume of methane produced will be 3.75ml
Answered by
9
Answer:2.24lit
Explanation:
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