Question

The volume of o2 at stp required for the complete combustion of 4g ch4 is

Answer 1

hope this is the correct one...

Answer 2

Answer: 11.2L

Explanation: CH4 REACTS COMPLETELY WITH O2

THEREFORE   PRODUCTS CO2 AND H2O

BALANCED EQUATION

CH4 + O2  gives  CO2 + 2H2O

16G OF CH4 REACTS WITH 22.4L OF O ( AT STP )

THEREFORE 4G OF CH4 REACTS WITH ? OF O

? = 22.4 * 4 = _ / 16

5.6 L OF O  THEREFORE 5.6 * 2 OF O2

11.2 L OF O2