Question

The volume of O2 obtained at STP, when 12.25 g of KClO3 is decomposed, is (Molar mass of KClO3 = 122.5 g/mol) 2.24 L 1.12 L 3.36 L 4.48 L

Answer 1

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The chemical equation for decomposition of KClO

The chemical equation for decomposition of KClO 3

The chemical equation for decomposition of KClO 3

The chemical equation for decomposition of KClO 3 written as:

The chemical equation for decomposition of KClO 3 written as:2KClO 3 → 2KCl+3O 2

245 g of KClO 3

245 g of KClO 3

gives 67.2 L of O 2

gives 67.2 L of O 2

gives 67.2 L of O 2 at STP. 12.25 g of KClO 3

12.25 g of KClO 3

12.25 g of KClO 3 gives 245 67.2 ×12.25 =3.36