Question

the volume of one moleculeof water.

Answer 1

Answer:

1 mole of water = 6.022 x 10^23 molecules of water, So 55.5 moles of water = 55.5 x 6.022 x 10^23 = 3.34 x 10^25 molecules of water. The gram molecular mass of water is 18.02. Thus volume occupied by 1 H2O molecule is 2.99 ×10-23 ml.

Answer 2

Answer: 23 ml H₂O

Explanation:

We can find this through a few steps:

Convert molecules to moles via Avogadro's number

Convert moles to grams via molar mass

Convert grams to cubic centimeters (milliliters) via density

Step 1:

We'll first convert the one molecule of water to moles, using Avogadro's number:

1molecule H₂O(1lmol H₂O6.022×1023molecules H₂O)

=1.66×10−24 mol H₂O

Step 2:

Now, using the molar mass of water (

18.02 g/mol), we'll calculate the number of grams:

1.66×10−24mol H₂O(18.02lg H₂O1mol H₂O)

=2.99×10−23g H₂O

Step 3:

Finally, knowing that 1g water occupies a volume of 1cm3 (or 1mL, which is more conventional for liquids), we can calculate the volume occupied by one molecules of water:

2.99×10−23g H₂O(1lmL1g H₂O)

=2.99×10−23 mL H₂O

I really hope this helped you (^_^)