The volume of oxygen required for complete combustion of 0.25 cm³ of CH₄ at S.T.P is _______ cm³.
(A) 0.25
(B) 0.5
(C) 0.75
(D) 1
Answers
Answered by
2
The ans would be 0.5 cm^3
Answered by
0
Dear friend,
● Answer -
(A) 0.25 cm³
● Step-by-step explanation -
Combustion of methane occurs as follows -
CH4(g) + O2(g) --> CO2(g) + 2H2O(l)
From the reaction we can say that, 1 volume of CH4 requires 1 volume of oxygen to burn at STP.
Therefore, 0.25 cm³ of oxygen is required for combustion of 0.25 cm³ of methane.
Thanks for asking. Hope this helped you..
● Answer -
(A) 0.25 cm³
● Step-by-step explanation -
Combustion of methane occurs as follows -
CH4(g) + O2(g) --> CO2(g) + 2H2O(l)
From the reaction we can say that, 1 volume of CH4 requires 1 volume of oxygen to burn at STP.
Therefore, 0.25 cm³ of oxygen is required for combustion of 0.25 cm³ of methane.
Thanks for asking. Hope this helped you..
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