Math, asked by kumermanish35, 5 months ago

The volume of the cone whose vertical height is 8 m
and the area of base 156 m²is
(A) 416 m
(B) 415 m
(C) 312 m
(D) 468 m​

Answers

Answered by aadya4836
0

Step-by-step explanation:

Solution

Given the vertical height of cone is 8 m and area of base is 156 sq m

Let radius of cone is r m 

Then base area =πr2=156⇒r2=156πmπr2=156⇒r2=156πm

And the volume of cone=13πr2h=13×156π×8=416m3

Answered by RudranshuMishra7
3

Area of base of a cone = πr²

height = 8m = h

Volume of a cone

1/3πr²h

  \mathtt{ \frac{1}{3}  \times Area  \: of  \: base \times height} \\  \\   \mathtt{\frac{1}{3}  \times 156 \times 8} \\  \\  \mathtt{52 \times 8} \\  \\     \fbox \pink{\boxed{\boxed{\mathtt{416 {m}^{3} }}}}

Option A) 416m³

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