Question

the volume of the gas in a vessel is 2 into 10 power minus 3 metre cube and its pressure is 1atm the gas is compressed by the 4 ATM pressure at constant temperature find the resulting volume.​

Answer 1

Explanation:

Solution:

PV=nTR

⇒10×

5

×1=n(83.14)×300

⇒n=

(83.14+300)

10

5

∴n=40

change in internal energy is given as 10

4

Joule

⇒du=10

4

=

n

C

V

dT

[pressure is constant so,vαTv

1

=v and v

2

=2v so, T

1

=300kT

2

=600k

Now, Heat supplied=dθ=

n

C

p

dT

=n(C

v

+R)dT

=40(8.21+0.833)×(600−300)

=40(9.043)×300

=110000j

=11×10

4

j