The volume of the two spheres is in the ratio 64: 27 . Find the difference of their surface areas, if the sum of their radii is 7.
Answers
Answered by
281
Ratio of volumes of two spheres = 64:27
(4/3 πr₁³)/(4/3 πr₂³) = 64/27
r₁³/r₂³ = 4³/3³
(r₁/r₂)³ = (4/3)³
r₁/r₂ = 4/3
r₁ = 4 and r₂ = 3 as their sum is equal to 7.
Difference of their surface areas :
= 4πr₁² - 4πr₂²
= 4π (r₁² - r₂²)
= 4π (4² - 3²)
= 4π (16-9)
= 4π (7)
= 4(22/7) (7)
= 88 units
Hope it helps
(4/3 πr₁³)/(4/3 πr₂³) = 64/27
r₁³/r₂³ = 4³/3³
(r₁/r₂)³ = (4/3)³
r₁/r₂ = 4/3
r₁ = 4 and r₂ = 3 as their sum is equal to 7.
Difference of their surface areas :
= 4πr₁² - 4πr₂²
= 4π (r₁² - r₂²)
= 4π (4² - 3²)
= 4π (16-9)
= 4π (7)
= 4(22/7) (7)
= 88 units
Hope it helps
swapnil756:
thnk u sooo much for this awsm ans
^_^
Answered by
66
Answer:Ratio of volumes of two spheres = 64:27
(4/3 πr₁³)/(4/3 πr₂³) = 64/27
r₁³/r₂³ = 4³/3³
(r₁/r₂)³ = (4/3)³
r₁/r₂ = 4/3
r₁ = 4 and r₂ = 3 as their sum is equal to 7.
Difference of their surface areas :
= 4πr₁² - 4πr₂²
= 4π (r₁² - r₂²)
= 4π (4² - 3²)
= 4π (16-9)
= 4π (7)
= 4(22/7) (7)
= 88 units
Similar questions