the volume of water flowing per second through a pipe is gieven by the product of area of cross section of the pipe and the speed of water flowing through it per second. write an expression for the water flowing per second through a rectangular pipe dimensions (x-9)cm×(x+10)cm if the speed of water is (x-1)cm/s
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Answer:
x³-91x+90 cm³/sec
Step-by-step explanation:
area of cross section= lengh× breadth
= (x+10) (x-9)= x²+x-90 cm²
speed of water= (x-1) cm/second
thus, volume of flow of water per second
= area of cross section × speed of water
=( x²+x-90) × (x-1)
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ಓಕೆ given any answer please
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