Question

The volume of water in a tank is 7 and when it is full is the length and breadth of the tank and 150 cm and 15 CM respectively find the height of the tank

Answer 1

Correct Question :

The volume of water in a tank is 7 litres when it is full and the length and breadth of the tank and 150 cm and 15 cm respectively find the height of the tank.

Given :

• Volume of water in the tank = 7 litres
• Length and breadth of the tank = 150 and 15 cm

To Find :

• Height of the tank

Solution :

The relation between litres and cm³ is given by ,

${\boxed {\rm{1litre = 1000 \: cm {}^{3} }}}$

Now ,

• 7 lites = 7000 cm³

We have ,

• Volume = 7000 cm³
• Length = 150 cm
• Breadth = 15 cm

Using the relation ,

$\boxed {\rm{volume = length \times breadth \times height}}$

$: \implies \rm \: 7000 = 150 \times 15 \times height \\ \\ : \implies \rm \: 7000 = 2250 \times height \\ \\ : \implies \rm \: height = \frac{7000}{2250} \\ \\ : \implies \rm \: height = 3\frac{1}{9} \: cm$

∴ The height of the tank is $\sf{3\dfrac{1}{9}}$ cm

Answer 2

Answer:

Correct Question :

The volume of water in a tank is 7 litres when it is full and the length and breadth of the tank and 150 cm and 15 cm respectively find the height of the tank.

Given :

Volume of water in the tank = 7 litres

Length and breadth of the tank = 150 and 15 cm

To Find :

Height of the tank

Solution :

The relation between litres and cm³ is given by ,

{\boxed {\rm{1litre = 1000 \: cm {}^{3} }}}

1litre=1000cm

3

Now ,

7 lites = 7000 cm³

We have ,

Volume = 7000 cm³

Length = 150 cm

Breadth = 15 cm

Using the relation ,

\boxed {\rm{volume = length \times breadth \times height}}

volume=length×breadth×height

\begin{gathered} : \implies \rm \: 7000 = 150 \times 15 \times height \\ \\ : \implies \rm \: 7000 = 2250 \times height \\ \\ : \implies \rm \: height = \frac{7000}{2250} \\ \\ : \implies \rm \: height = 3\frac{1}{9} \: cm\end{gathered}

:⟹7000=150×15×height

:⟹7000=2250×height

:⟹height=

2250

7000

:⟹height=3

9

1

cm

∴ The height of the tank is \sf{3\dfrac{1}{9}}3

9

1

cm