The volume of water must be added to 100 ml of 0.5 M NaOH solution to get 0.2M solution is
Answers
Explanation:
molarity of the solution initially : M1 .5 M
volume of the solution initially : V1 100 ml .1 litre
molarity of solution after dilution M2 : . 2M
volume of the solution after dilution V2: to be determined
Formula used: V1M1 equals to V2M2
then V2 equals to V1M1/M2 equals to .1 x.5/.2 equals to .25 litres equals to 250 ml
volume of solvent to be added to get the dilute solution : 250 ml - 100 ml equals to 150 ml
Ans : 150 ml
Answer:
The volume of water must be added to 100 mL of 0.5 M NaOH solution to get 0.2 M solution is
Solution
Solution - I (Initial or before dilution)
Solution – II (Final after dilution)
Volume of NaOH solution=V1=100 mL
Volume of NaOH =V2
Molarity,M1=0.5 M
Molarity,M2=0.2 M
According to Dilution Law,
M1V1=M2V2
The final volume of NaOH is
V2=M1V1M2=0.5×1000.2=250mL
Volume of water to be added =V2 − V1
=250−100
=150 mL