Chemistry, asked by crystalclear100, 1 year ago

the volume of water that must be added to a mixture of 250 ml of 0.6 M HCL and 750 ml of 0.2 M HCL to obtain 0.25 M solution of HCL

Answers

Answered by AJAYMAHICH
56

No. of moles of 0.6M HCl = 0.15

No. of moles of 0.2M HCl = 0.15

let V be the volume(in ml) of the 0.25M solution. No of moles present = 0.15+0.15 = 0.3



0.3*1000/v(ml) = 0.25 M

v = 1.2 lit.

Answered by abhijith91622
0

Final answer: The volume of water to be added to obtain a 0.25 M final solution is 200 mL.    

Given that: We are given a mixture of 250 mL of 0.6 M HCl and 750 mL of 0.2 M HCl.

To find: We have to find the volume of water that must be added to a mixture of 250 mL of 0.6 M HCl and 750 mL of 0.2 M HCl to obtain 0.25 M solution of HCl.

Explanation:

  • When two solutions of the same compound but they differ in molarity and volumes are added to obtain a new solution.

                     M_{1}V_{1}+M_{2}V_{2}= M_{final}V_{final}

  • Let M_{1}, M_{2}, V_{1} and V_{2} are the molarity and volume of the solutions of same compound being mixed. And M_{final} and V_{final} are the molarity and volume of the final solution being formed.
  • Here, two solutions of HCl of different molarity and volume are mixed to form a new solution.

M_{1} = 0.6M

M_{2} = 0.2 M

V_{1} = 250 mL

V_{2} = 750 mL

M_{final} = 0.25 M

V_{final} = ?

  • Substitute these values in:

                      M_{1}V_{1}+M_{2}V_{2}= M_{final}V_{final}

                 (0.6\times250)+(0.2\times750)=0.25\times V_{final}

                               150+150=0.25\times V_{final}\\\\300=0.25\times V_{final}

                               V_{final}=\frac{300}{0.25}

                               V_{final}=1200 mL

  • Total volume of the final solution V_{final} = 1200 mL
  • The volume of the solution initially mixed, V_{initial}=V_{1}+V_{2}

                                                                  = 250+750=1000 mL

  • The volume of water we need to add to the initial solution to make the final solution = V_{final}-V_{initial}

                                                 = 1200-1000

                                                 = 200 mL

  • Hence, the volume of water to be added to obtain a 0.25 M final solution is 200 mL.

To know more about the concept please go through the links

https://brainly.in/question/3206766

https://brainly.in/question/19654715

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