Question

The volume required to prepare 2.0L of 3.0M H2SO4 solution from 96% H2SO4 solution (density 1.83gmL−1) is

Answer 1

Amount of HCl in 2.0L of 3.0M solution =(2.0L)(3.0molL−1)=6.0mol

Mass of H2SO4 in this solution=(6.0mol)(98gmol−1)=588g

Mass of 96% H2SO4 solution containing 588g of H2SO4=588×100g/96=612.5g

Volume of 96% H2SO4 solution weighing 612.5g/1.83gmL−1=334.7mL