The volume vof a cuboid is 3600 cm and its height is 12 cm . If the lenght is 3/4 of the breadth, then find the total surface area of the cuboid.
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Answered by
0
Answer:
Step-by-step explanation:
volume of cuboid= l*w*h
h= 12cm
b=b
l=
vol. of cuboid=3600
=12*b*3b/4
⇒36b²/4
⇒9b²=3600
⇒b²=400
⇒b=20
∴l=15cm -----(l=3b/4)
surface area of cube= 2lb+2lh+2hb
⇒2(15)(20)+2(15)(12)+2(12)(20)
⇒600+360+480
⇒1440cm
Answered by
0
let the breadth be X.
So,
x × 3x/4 × 12 = 3600
3x^2/4 × 12 = 3600
9x^2 = 3600
x^2 = 400
x = 20
Now, Breadth=20
Length=15
Height=12
Therefore, total surface area=2[(20×15)+(15×12)+(12×20)]
=2(300+180+240)
=2×720
=1440.
I think that it will help.
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