Question

The volumne of conical tent is 1232 m*m*m and area of the basr 154m*m calculate radius of the floor height the tent, lenght of the canvas required to cover this conical tent if its width is 2m

Answer 1

$\large \tt AHOY!! \:$

given the volume of the conical tent = 1232m^3

area of the base = 154m^2

we know that the base of a cone is circular.

so we can write,

=> πr^2 = 154m^2

=> 22/7 × r^2 = 154m^2

=> r^2 = 154/1 × 7/22

=> r^2 = 7 × 7

=> r^2 = 49

=> r = √49

=> r = 7

the radius of the conical tent is 7m.

now, it's given that the volume of the conical tent is 1232m^3

and the formula for the volume of a cone is 1/3πr^2h

therefore 1/3πr^2h = 1232m^3

=> 1/3 × 22/7 × 7 × 7 × h = 1232m^3

=> 22/3 × 7 × h = 1232m^3

=> 154/3 × h = 1232m^3

=> h = 1232/1 × 3/154

=> h = 8 × 3

=> h = 24m

height of the conical tent = 24m.

for finding the CSA of the conical tent, first we need to find it's slant height.

→ l²(slant height) = r²(radius) + h²(height)

→ l² = 7² + 24²

→ l² = 49 + 576

→ l² = 625

→ l = √625

→ l = 25m

hence, the slant height of the conical tent is 25m.

therefore CSA of the conical tent = area of canvas required

= πrl

= 22/7 × 7 × 25

= 22 × 25

= 550m^2

given width of the canvas = 2m

therefore length of the canvas = 550/2

= 275m

$\large \tt HOPE \: THIS \: HELPS!!$