The water in a tank is pressurized by air, and the pressure is measured by a multi-fluid manometer as shown in fig. the tank is located on a mountain at an altitude of 1400 m where the atmospheric pressure is 85.6 kpa. determine the air pressure in the tank if h1 = 0.1 m, h2 = 0.2 m, and h3 =0.35 m. take the densities of water, oil, and mercury to be 1000 kg/m3, 850 kg/m3, and 13,600 kg/m3, respectively.
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Given:
The altitude of the tank = 1400 m
The pressure at 1400 m = 85.6 kpa
h1 = 0.1 m, h2 = 0.2 m, and h3 =0.35 m
The densities of water, oil, and mercury = 1000 kg/m³, 850 kg/m³, and 13,600 kg/m³, respectively
To Find:
Air pressure in the tank
Solution:
Pressure at point B (Refer the figure) = Pb
Pb =Pair + ροgh1 + ρwgh2 (calculated from the left side) -(1)
Now calculating from the right side,
Pb = Patm + ρmgh3 -(2)
Since equation 1 = equation 2
⇒ Pair + ροgh1 + ρwgh2 = Patm + ρmgh3
or Pair = Patm + ρmgh3 - ρwgh2 - ροgh1
Substituting the values, (taking g= 10m/s²)
Pair = 85600+46648−833−1960
= 130000 Pa
Hence, the air pressure in the tank is 130kPa.
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