the water is floating with the force of 40 Newton and pressure on the fluid is 4 Newton per metre square then the force of water actor on the area is
Answers
Answer:
pressure= force/area
4 = 40/area
area = 40/4 = 10m^2
First, we use the definition of density
ρ
=
m
V
to find the steel’s volume, and then we substitute values for mass and density. This gives
V
st
=
m
st
ρ
st
=
1
.
00
×
10
7
kg
7
.
8
×
10
3
kg/m
3
=
1
.
28
×
10
3
m
3
.
Because the steel is completely submerged, this is also the volume of water displaced, Vw. We can now find the mass of water displaced from the relationship between its volume and density, both of which are known. This gives
m
w
=
ρ
w
V
w
=
(
1.000
×
10
3
kg/m
3
)
(
1.28
×
10
3
m
3
)
=
1.28
×
10
6
kg.
By Archimedes’ principle, the weight of water displaced is mwg, so the buoyant force is
F
B
=
w
w
=
m
w
g
=
(
1.28
×
10
6
kg
)
(
9.80
m/s
2
)
=
1.3
×
10
7
N
.
The steel’s weight is
m
w
g
=
9
.
80
×
10
7
N
, which is much greater than the buoyant force, so the steel will remain submerged. Note that the buoyant force is rounded to two digits because the density of steel is given to only two.