the water vapour pressure of solution containing 108.24g of a non volatile solute dissolved in 1000g of water at 293 kelvin is 17.354mm hg. the vapour pressure of water at 293 kelvin is 1754mm of hg.assuming the solution to be ideal. calculate the molar mass of the solute.
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molar mass of solute is 2g/mol
mass of solute = 108.24 g
mass of solvent = 1000g
molar mass of water = 18 g/mol
let molar mass of solute is M.
we know, change in pressure/pressure of pure water vapor = no of mole of solute/no of mole of solvent.
⇒(1754 - 17.354)/1754 = (108.24/M)/(1000/18)
⇒1736.646/1754 = 108.24 × 18/1000M
⇒M = (108.24 × 18 × 1754)/(1000 × 1736.646)
= 1.967 ≈ 2g
hence, molecular weight of solute is 2g/mol
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