Question

the wave length of a microscopic particle of mass 9.1×10^-3 kg 182 nm it's Kinetic energy in joules is​

Answer 1

ANSWER

lamda = h /mv ( this formula is used in optics given by debroglie ) ( wavelength used here is not a normal wavelwngth it relates wave nature with particle nature so we can use here)

v = h / m × lamda

1/2 m v^2 = h^2

2m lamda

on solving we get

0.1098901 × 10^ -56

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