Physics, asked by ruchikarajput3624, 1 year ago

The wave length of radiation required to remove the electron of hydrogen atom(ionization energy )from n=2 orbit to n= is

Answers

Answered by smartAbhishek11
0
also is there answers is 2
Answered by Anonymous
38

Answer:

n1 = 1 (Ground Level)

n2 = 3(Excited state)

Rh = Rydberg constant = 10 973 731.6 m-1λ

= wavelength.v

= frequency.

The and formula we will use is

:Putting values :

1/ λ = 10 973 731.6 * (1 - 1/9)1/ λ

= 10 973 731.6 * 8/91/ λ

= 9754428.09λ

= 1.025 * 10^-7

mUsing v * λ

= c (c c= speed of light = 3 * 10^8)

v = c / λv

= 2.92 * 10^15 sec^-1

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