Question

the wave length of spectral line emitted  by hydrojen atom in the lyman series is 16/15R cm. what is the value of n2

Answer 1

$v=R( \frac{1}{n_1^2}- \frac{1}{n_2^2} )$
v=1/lambda=1/(16/15R)=15R/16
for lyman n1=1
$\frac{15R}{16}=R( \frac{1}{1^2}- \frac{1}{n^2} ) \\ 1-\frac{15}{16}= \frac{1}{n_2^2} \\ \frac{1}{n_2^2} = \frac{1}{16}$
$n_2^2=16 \\ n_2=4$

Answer 2

Answer:

n2=4is the answer .please mark as brainlist